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In Fig. 6.18, ABC is a triangle right angled at B and BD ⊥ AC. If AD = 4 cm, and CD = 5 cm, find BD and AB
Ques 30 (MCQ) - In figure, ∠ACB = ∠CDA, AC = 8cm, AD = 3cm, then BD is
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![In Fig. 6.2, ∠BAC = 90° and AD ⊥ BC. Then - [MCQ] - NCERT Exemplar](https://d1avenlh0i1xmr.cloudfront.net/c8d4beda-f648-433a-a8b4-9eabf91ddf6e/slide6.jpg "In Fig. 6.2, ∠BAC = 90° and AD ⊥ BC. Then - [MCQ] - NCERT Exemplar")
In Fig. 6.2, ∠BAC = 90° and AD ⊥ BC. Then - [MCQ] - NCERT Exemplar
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In the given figure, AD bisects A, AB = 12 cm, AC = 20 cm and BD = 5 cm, determine CD.
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Using ruler and compasses, construct a parallelogram ABCD give that AB = 4 cm, AC = 10 cm, BD = 6 cm.
![kwat T ab AB ac bd [9] The thin-walled section is | Chegg.com](https://media.cheggcdn.com/media/dc6/dc643794-7276-4a1c-a13f-2d000bd30c7d/phpa5FERN "kwat T ab AB ac bd [9] The thin-walled section is | Chegg.com")
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![In Fig. 6.2, ∠BAC = 90° and AD ⊥ BC. Then - [MCQ] - NCERT Exemplar](https://d1avenlh0i1xmr.cloudfront.net/d059aa6a-e68f-40dc-9d20-d198548a94b7/slide7.jpg "In Fig. 6.2, ∠BAC = 90° and AD ⊥ BC. Then - [MCQ] - NCERT Exemplar")
In Fig. 6.2, ∠BAC = 90° and AD ⊥ BC. Then - [MCQ] - NCERT Exemplar
Selina Solutions Class 9 Concise Maths Chapter 10 Isosceles Triangles -Download Free PDF
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