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In any triangle ABC, prove that AB^2 + AC^2 = 2(AD^2 + BD^2) , where D is the midpoint of BC.
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Example 10 - ACB = 90 and CD perpendicular AB. Prove BC2/AC2
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ABD is a triangle right angled at A and AC ⊥ BD. Show that (i) AB² = BC.BD ( ii) AC² = BC.DC (iii) AD² = BD.CD
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